Relativity of Time Activity

Question 1: The distance is greater for the moving frame than for the stationary one.
Question 2: The moving frame will experience a longer time interval.
Question 3: No, the rider would experience the same result as the stationary frame because it is the equivalent of a stationary frame of reference.
Question 4: There would be less of a difference in time experienced if the velocity was decreased because the distance the light traveled in the moving frame of reference would decrease.
Question 5: It would be the time measured by the observer riding the light clock multiplied by the Lorentz factor. in this case it is 8x10^-6 seconds for a time of 6.67x10^-6 and a Lorentz factor of 1.2.
Question 6: The Lorentz factor would have to be 1.1169