Tuesday, May 28, 2013

Experiment 15: Planck's Constant From and LED

Introduction: The purpose of this activity is to experimentally determine the value of Planck's Constant using a diffraction grating and a variety of LED's

Activity One: The energy given to an electron under a a potential difference is E=qV where q is the charge of an electron and V is the voltage potential difference. The energy of an electron also is (h•c)/lambda where h is Planck's constant, c is the speed of light, and lambda is the wavelength of the light source. Setting them equal to each other, we get q•V=(h•c)÷lambda. Solving for h, we get h=(q•v•lambda)÷c.
Activity Two: Procedure: We attached a resistor to the positive of a voltage source set at 3 volts and one end of and LED. We then attached the Other end of the LED to the negative of a voltage source. We then set up a two meter stick with a diffraction grating at the end opposed to the LED and a one meter stick perpendicular to the first.

We looked through the diffraction grating and marked on the one meter stick where the spectrum began and ended. We did this for all the colored LED's and noted the voltage.

Data and Analysis: Here is the data collected on all of the different colors of LED's. We used the same formula from light and spectra (lambda = (d•D)÷√(L^2–D^2)) to find the wavelength of all the LED's. The value of d is given as a difference because the spectrum is not just a line, rather a smear. All of our group members looked through the grating to give 3 trials for every color
The colored LED's only displayed their color when looking through the diffraction grating for the most part. As observed in the picture, blue displays mostly blue a slight bit of green and green displays mainly green a small amount of blue. Yellow, however, displays a little red, orange and green on top of the yellow. The most likely explanation for this is the LED's are not pure forms of their color. In the case of yellow, the shade of yellow is emitting a larger portion of the visible spectrum than just yellow but the majority of the light emitted is yellow. Of course, white emits the entire spectrum. The LED with the largest error is yellow. This is due to the width of the spectrum displayed as just discussed. Below are the data and calculations for lambda and Planck's constant as well as the uncertainty associated. It was planned that we would graph Voltage versus 1/lambda, however this gave a split graph and threw of the linear fit of the slope, which would give Planck's constant. To correct this, we found the value of Planck's constant using the formula from activity one for every color and averaged them. This gave us a more accurate value for Planck's constant.
Questions: We did not see a relationship between wavelength other than green and blue used more voltage than yellow and red. This makes sense because those are more high energy wavelengths. This can be applied to sunset being red and the sky being blue. The sunset will be red because red is a less energetic wavelength and will be refracted by the atmosphere last.

Experiment 14: Color and Spectra

Introduction: The purpose of this experiment is to measure the wavelengths of the various colors in the light spectra as well as observe the colors emitted by single elements using a diffraction grating.

White Light Procedure: We placed a light source on a table and attached a diffraction grating to a 2 meter stick touching the light source. We then put another meter stick perpendicular the first touching the light source
We then looked through the diffraction grating and observed the entire light spectrum and marked where the various colors began and ended.

Data and Analysis: The diagram and formula below was used to find the wavelengths expressed in visible light
The work for finding the wavelength and the uncertainty associated is below. The actual value is also compared. Our data is supported fairly well.

Single Element Procedure: 
The set up is the same as with the white light source except the light source was replaced with a hydrogen gas tube.
The tube was looked at through the diffraction grating and only three lines were visible. There are actually 4 but only 3 can be seen.
Data and Analysis: We used marked the meter stick where the lines were and used the same formula to calculate the wavelength with uncertainty for the three lines.
The actual wavelengths visible for hydrogen are 410, 434, 468, and 656 nm. only the 434 nm is within uncertainty. This is probably due to the fact that the meter sticks were not exactly touching the hydrogen tube and the diffraction grating was a cheap plastic one.

Monday, May 27, 2013

Experiment 13: Polarization of Light

Introduction: The purpose of this experiment is to witness the polarizing of light and its effect. This is achieved by observing light through a number of polarizing filters and collecting data.
Preliminary Questions:
1) When the polarizing filters are perpendicular to each other, no light is able to pass through. It looks black
2) This is a graph of light intensity versus Rotation angle from 0 to 180 degrees

Procedure:
We attached two polarizing filters to a meter stick in front of a light source and secured alight sensor to it. The polarizing filters were positioned so the most amount of light would come through and were marked. They were then rotated so the least amount of light would come through and were marked. The brightest angle is referred to as 0º and the darkest as 90º
We then collected data on light intensity versus angle of rotation and rotated the second polarizer 7.5º at a time clockwise until we turned 90º. We then did the same thing counterclockwise.

We then moved the second polarizer out of the way and we adjusted a third polarizer to block out as much light as possible and then replaced the second polarizer at the 0º position. We rotated the second one 7.5º at a time just as in the previous step and generated another graph
We then looked at florescent light through a polarizer and then the reflection from a florescent light on the table

Data and Analysis: 
For the two polarizers
The first graph explains that the polarizer filters out light as a function of angle as a sin pattern. This means as you turn it from parallel, the light becomes less and less intense until tapering off to zero, and then it gradually becomes brighter, then quickly becomes brighter, and then brightness slows its speed until you have turned it 180º. The cos^2 graph vs illumination is linear.

For three polarizers
Our graph does not reflect what should happen. Since the first and last lens are perpendicular to each other, the light should not come out, however the middle lens shifting some of the light emitted from the first lens so all of the light is not blocked by the third lens. This means that 45º should yield the most light because it creates the least similar alignment with either the first or third lens. Towards the end of our graph, this becomes clear.

When looking directly at the florescent lights through the polarizing filter, there is no observable change when the filter is rotated. This is because florescent lights are random emitters of light, meaning that they release light at all orientations. If the rotation cancels one, a new one will replace it. This is not so with the reflection of light. The table is not a perfectly reflective surface so the contours of the table partially orient the light. The polarizing lens is able to block light of the specific orientation so when rotated, the reflection of the light will darken.

Experiment 12: CD Diffraction

Introduction: The purpose of this procedure is to measure the distance between the burned in grooves of a CD using a laser by analyzing its diffraction pattern.

Procedure: We first found the wavelength (lambda) for the laser. We did this by shining a laser through a diffraction grating at a wall. We measured the distance from the grating to the wall (L) and found the distance between the slits on the grating (d) by dividing .001 meters by 600, because that was the number of lines per millimeter. We also determined theta by measuring the distance between the primary laser spot and the brightest maxima (y) and using some trig identities.

We then cut a hole in a piece of paper and held it upright over the table parallel to a CD.

We measured the distance between the CD and the paper and directed the laser through the hole onto the CD. We then measured the distance between the middle and one of the outer laser dots.

Data and Analysis: 
This is the calculation for theta from the first picture with uncertainty.
This is the calculation for the wavelength of the laser with uncertainty. The value printed on the laser was 650 nm so our result is confirmed.

This is the calculation for the distance between the groves in  the CD (d).

This is the percentage error of the industry standard of the distance between the groves (1600 nm) and the experimental value.

We found uncertainty for all values by finding the maximum and minimum values of the required variable which were as a result of uncertainty in measurement. We then average the max and min and subtracted the average from the max, and the min from the average. For d, the value was found to be 1573.5 nm ± 189.5 nm. The industry standard is within this uncertainty value so our results are confirmed.

Sunday, May 26, 2013

Experiment 11: Measuring a Human Hair



Introduction: The purpose of this experiment is to use diffraction to accurately measure a human hair. The measurement will be confirmed with a micrometer.
Procedure: We hole punched a card and taped a hair taught over the hole. We then shined a laser through the hole, over the hair.

We then measured the distance from the card to the wall we would project the laser beam on with a 2 meter stick. This value is referred to as L.

We measured the spaces between the bright spots of the interference pattern, noting the uncertainty of the measurement. This value is referred to as y. The wavelength (represented as lambda) was stated on the laser.

Data and Analysis:

We used the formula in the picture and solved for d. In this formula, d is the measure of the gap between the light beam that causes the interference pattern. In this case, it is the diameter of the hair. We then calculated the maximum and minimum values of d, which came from the uncertainty in the measurement of y. We averaged them together and then subtracted the average from the maximum of d, and the minimum of d from the average. This gave the uncertainty of d. This yields the value of d  to be 5.4e -5 ± 0.25e -5. This measurement makes sense because the hair must be on the order of magnitude of the laser wavelength or smaller to cause interference. This answer is smaller than 650 nm. The d experimental is the measurement of hair obtained by the micrometer. It is not within uncertainty however, this is likely because the micrometer was not calibrated before measurement and was in a very used condition. It is on the same order of magnitude so we were in the right ballpark with a percentage error of 25.9%

Monday, May 13, 2013

Potential Wells


1. The ground state was 2.1 MeV regardless of a finite or infinite potential well.
2. The first excited state was 8.4 MeV for the infinite potential well. It is not possible for the 8.4 MeV to exist in the finite potential well.
3. The energy of the first excited state is higher in the infinite well than the finite because the wavelength is larger for the finite potential well which translates to lower energy.
4. When the potential well is lowered, the particle's energy is closer to the top of the potential well which means it can penetrate deeper
5. It will penetrate less

Potential Energy Diagrams

1. The range of motion will be between -5 cm and 5 cm.
2. The particle can not cross the barrier because its total energy is less than that of the potential barrier.
3. There is more of a chance of detecting the particle between -5 cm and 0 cm because the potential is higher there than between 0 cm and 5 cm. This means that you must subtract the potential from total to get kinetic in the region -5 cm to 0 cm which is smaller than the kinetic in the region 0 cm to 5 cm where the potential is 0.
4. The motion will increase by a factor of root 2.
5. It will be an upside-down parabola.
6. Near the endpoints of the graph because the particle is moving slower at the ends.